EquationsMCQPYQ Nov 19Question 1055 of 221
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Find the value of K\displaystyle K in 3x22kx+5=0\displaystyle 3x^2 - 2kx + 5 = 0 if x=2\displaystyle x = 2

Options

A174\displaystyle \frac{17}{4}
B714\displaystyle -\frac{7}{14}
C417\displaystyle \frac{4}{17}
D417\displaystyle -\frac{4}{17}
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Correct Answer

Option a174\displaystyle \frac{17}{4}

All Options:

  • A174\displaystyle \frac{17}{4}
  • B714\displaystyle -\frac{7}{14}
  • C417\displaystyle \frac{4}{17}
  • D417\displaystyle -\frac{4}{17}

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Detailed Solution & Explanation

Given the quadratic equation:
3x22kx+5=03x^2 - 2kx + 5 = 0
Since x=2\displaystyle x = 2 is a root of the equation, it must satisfy the equation.
Substitute x=2\displaystyle x = 2 into the equation:
3(2)22k(2)+5=03(2)^2 - 2k(2) + 5 = 0
3(4)4k+5=03(4) - 4k + 5 = 0
124k+5=012 - 4k + 5 = 0
174k=017 - 4k = 0
4k=17    k=1744k = 17 \implies k = \frac{17}{4}
This matches Option a.
**Option a**

About This Chapter: Equations

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Linear, Quadratic and Cubic Equations

This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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