EquationsMCQPYQ Jun 22Question 1058 of 221
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If the second root of the given equation is reciprocal of first root then value of 'K' in the equation 5x213x+K=0\displaystyle 5x^2 - 13x + K = 0

Options

A3
B2
C1
D5
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Correct Answer

Option d5

All Options:

  • A3
  • B2
  • C1
  • D5

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Detailed Solution & Explanation

Given the quadratic equation:
5x213x+K=05x^2 - 13x + K = 0
Let the two roots of the equation be α\displaystyle \alpha and 1α\displaystyle \frac{1}{\alpha} (reciprocals of each other).
According to Vieta's formulas, the product of the roots is given by ca\displaystyle \frac{c}{a}:
Product of roots=α1α=K5\text{Product of roots} = \alpha \cdot \frac{1}{\alpha} = \frac{K}{5}
1=K5    K=51 = \frac{K}{5} \implies K = 5
Therefore, the value of K\displaystyle K is 5\displaystyle 5, which corresponds to Option d.
**Option d**

About This Chapter: Equations

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Linear, Quadratic and Cubic Equations

This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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