EquationsMCQPYQ Dec 22Question 1059 of 221
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If the roots of the equation x2px+q=0\displaystyle x^2 - px + q = 0 are in the ratio 2:3\displaystyle 2:3, then:

Options

Ap2=25q\displaystyle p^2 = 25q
Bp2=6q\displaystyle p^2 = 6q
C6p2=25q\displaystyle 6p^2 = 25q
Dp2=25q\displaystyle p^2 = 25q
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Correct Answer

Option c6p2=25q\displaystyle 6p^2 = 25q

All Options:

  • Ap2=25q\displaystyle p^2 = 25q
  • Bp2=6q\displaystyle p^2 = 6q
  • C6p2=25q\displaystyle 6p^2 = 25q
  • Dp2=25q\displaystyle p^2 = 25q

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Detailed Solution & Explanation

Given the quadratic equation:
x2px+q=0x^2 - px + q = 0
Let the roots be in the ratio 2:3\displaystyle 2:3, so we can assume the roots are 2k\displaystyle 2k and 3k\displaystyle 3k.
According to Vieta's formulas:
1) Sum of roots:
2k+3k=(p)    5k=p    k=p5(1)2k + 3k = -(-p) \implies 5k = p \implies k = \frac{p}{5} \quad \dots (1)
2) Product of roots:
(2k)(3k)=q    6k2=q(2)(2k)(3k) = q \implies 6k^2 = q \quad \dots (2)
Substitute the value of k\displaystyle k from equation (1) into equation (2):
6(p5)2=q6\left(\frac{p}{5}\right)^2 = q
6(p225)=q6\left(\frac{p^2}{25}\right) = q
6p225=q    6p2=25q\frac{6p^2}{25} = q \implies 6p^2 = 25q
This is the correct relation, which matches Option c.
**Option c**

About This Chapter: Equations

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Linear, Quadratic and Cubic Equations

This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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