EquationsMCQMTP Oct 21Question 1085 of 221
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The roots of the equation x2x+1=0\displaystyle x^2 - x + 1 = 0 are

Options

AImaginary and unequal
BReal and unequal
CReal and equal
DImaginary and equal
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Correct Answer

Option aImaginary and unequal

All Options:

  • AImaginary and unequal
  • BReal and unequal
  • CReal and equal
  • DImaginary and equal

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Detailed Solution & Explanation

Given the quadratic equation:
x2x+1=0x^2 - x + 1 = 0
Here, a=1\displaystyle a = 1, b=1\displaystyle b = -1, and c=1\displaystyle c = 1.

Let us calculate the discriminant D\displaystyle D:
D=b24acD = b^2 - 4ac
Substitute the coefficients:
D=(1)24(1)(1)=14=3D = (-1)^2 - 4(1)(1) = 1 - 4 = -3
Since the discriminant D<0\displaystyle D < 0, the roots of the equation are complex numbers, which are imaginary and unequal.
This corresponds to Option a.

**Option a**

About This Chapter: Equations

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Linear, Quadratic and Cubic Equations

This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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