EquationsMCQMTP Dec 22 - Series 1Question 1090 of 221
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If roots of equation x2+x+r=0\displaystyle x^2 + x + r = 0 are α\displaystyle \alpha and β\displaystyle \beta and α3+β3=6\displaystyle \alpha^3 + \beta^3 = -6. Find the value of 'r'

Options

A5/3\displaystyle -5/3
B7/3\displaystyle 7/3
C4/3\displaystyle 4/3
D1\displaystyle 1
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Correct Answer

Option a5/3\displaystyle -5/3

All Options:

  • A5/3\displaystyle -5/3
  • B7/3\displaystyle 7/3
  • C4/3\displaystyle 4/3
  • D1\displaystyle 1

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Detailed Solution & Explanation

Given the quadratic equation:
x2+x+r=0x^2 + x + r = 0
From Vieta's formulas, the sum and product of the roots are:
α+β=1\alpha + \beta = -1
αβ=r\alpha\beta = r
We are given that α3+β3=6\displaystyle \alpha^3 + \beta^3 = -6.
Recall the algebraic identity:
α3+β3=(α+β)33αβ(α+β)\alpha^3 + \beta^3 = (\alpha + \beta)^3 - 3\alpha\beta(\alpha + \beta)
Substitute the known values into the identity:
6=(1)33(r)(1)-6 = (-1)^3 - 3(r)(-1)
6=1+3r-6 = -1 + 3r
5=3r    r=53-5 = 3r \implies r = -\frac{5}{3}
This corresponds to Option a.

**Option a**

About This Chapter: Equations

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Linear, Quadratic and Cubic Equations

This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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