Sequence and SeriesMCQMTP Oct 21Question 1800 of 212
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Find the sum of first twenty-five terms of A.P. series whose nth\displaystyle n^{th} term is (n+25)\displaystyle \left(n+\frac{2}{5}\right)

Options

A105
B115
C125
D135
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Correct Answer

Option b115

All Options:

  • A105
  • B115
  • C125
  • D135

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Detailed Solution & Explanation

The nth\displaystyle n^{\text{th}} term is tn=n+25\displaystyle t_n = n + \frac{2}{5}.
Let's find the first term (t1\displaystyle t_1) and the 25th\displaystyle 25^{\text{th}} term (t25\displaystyle t_{25}):
t1=1+25=75t_1 = 1 + \frac{2}{5} = \frac{7}{5}
t25=25+25=1275t_{25} = 25 + \frac{2}{5} = \frac{127}{5}

The sum of the first 25\displaystyle 25 terms is:
S25=252[t1+t25]S_{25} = \frac{25}{2} [t_1 + t_{25}]
S25=252[75+1275]S_{25} = \frac{25}{2} \left[\frac{7}{5} + \frac{127}{5}\right]
S25=252[1345]=51342=567=335S_{25} = \frac{25}{2} \left[\frac{134}{5}\right] = \frac{5 \cdot 134}{2} = 5 \cdot 67 = 335
Hence, the mathematically exact sum is 335\displaystyle 335.

About This Chapter: Sequence and Series

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Arithmetic & Geometric Progressions

This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.

View Official ICAI Syllabus

Exam Strategy Tip

For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.

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