Sequence and SeriesMCQMTP Dec 22 - Series 1Question 1804 of 212
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The first and last terms of an arithmetic progression are 5\displaystyle 5 and 905\displaystyle 905. Sum of the terms is 45,955\displaystyle 45,955. The number of terms is

Options

A99
B100
C101
D102
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Correct Answer

Option c101

All Options:

  • A99
  • B100
  • C101
  • D102

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Detailed Solution & Explanation

We are given:
First term a=5\displaystyle a = 5
Last term l=905\displaystyle l = 905
Sum of the terms Sn=45955\displaystyle S_n = 45955.

Using the sum formula:
Sn=n2[a+l]S_n = \frac{n}{2} [a + l]
45955=n2[5+905]45955 = \frac{n}{2} [5 + 905]
45955=n2[910]45955 = \frac{n}{2} [910]
45955=455n45955 = 455n
n=45955455=101n = \frac{45955}{455} = 101
Hence, **Option C** is the correct answer.

About This Chapter: Sequence and Series

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Arithmetic & Geometric Progressions

This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.

View Official ICAI Syllabus

Exam Strategy Tip

For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.

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