Sequence and SeriesMCQMTP March 22Question 1850 of 212
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In a GP, if fourth term is 3\displaystyle 3 then the product of first seven terms is

Options

A35\displaystyle 3^5
B37\displaystyle 3^7
C36\displaystyle 3^6
D34\displaystyle 3^4
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Correct Answer

Option b37\displaystyle 3^7

All Options:

  • A35\displaystyle 3^5
  • B37\displaystyle 3^7
  • C36\displaystyle 3^6
  • D34\displaystyle 3^4

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Detailed Solution & Explanation

Let the first term be a\displaystyle a and common ratio be r\displaystyle r.
The fourth term t4=ar3=3\displaystyle t_4 = ar^3 = 3.
The product of the first seven terms is:
Product=aarar2ar3ar4ar5ar6\text{Product} = a \cdot ar \cdot ar^2 \cdot ar^3 \cdot ar^4 \cdot ar^5 \cdot ar^6
Product=a7r21=(ar3)7\text{Product} = a^7 r^{21} = (ar^3)^7
Substitute ar3=3\displaystyle ar^3 = 3:
Product=37\text{Product} = 3^7
Hence, **Option B** is the correct answer.

About This Chapter: Sequence and Series

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Arithmetic & Geometric Progressions

This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.

View Official ICAI Syllabus

Exam Strategy Tip

For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.

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