Sets, Relations and FunctionsMCQPYQ Sep 24Question 1910 of 217
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A team has a total population of 50,000\displaystyle 50,000. Out of it 28,000\displaystyle 28,000 read the newspaper 'X' and 23,000\displaystyle 23,000 read newspaper 'Y', while 4,000\displaystyle 4,000 read both the newspaper. The number of persons not reading any of the two newspapers are:

Options

A3,000
B2,000
C2,500
D5,000
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Correct Answer

Option a3,000

All Options:

  • A3,000
  • B2,000
  • C2,500
  • D5,000

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Detailed Solution & Explanation

Let U\displaystyle U be the universal set representing the total population, so n(U)=50,000\displaystyle n(U) = 50,000.
Let X\displaystyle X be the set of people who read newspaper 'X', and Y\displaystyle Y be the set of people who read newspaper 'Y'. We are given:
- n(X)=28,000\displaystyle n(X) = 28,000
- n(Y)=23,000\displaystyle n(Y) = 23,000
- n(XY)=4,000\displaystyle n(X \cap Y) = 4,000
The number of people who read at least one of the two newspapers is given by the union n(XY)\displaystyle n(X \cup Y):
n(XY)=n(X)+n(Y)n(XY)n(X \cup Y) = n(X) + n(Y) - n(X \cap Y)n(XY)=28,000+23,0004,000=47,000n(X \cup Y) = 28,000 + 23,000 - 4,000 = 47,000
The number of people who do not read either newspaper is the complement of the union, which is:
n((XY)c)=n(U)n(XY)n((X \cup Y)^c) = n(U) - n(X \cup Y)n((XY)c)=50,00047,000=3,000n((X \cup Y)^c) = 50,000 - 47,000 = 3,000
Hence, **Option A** is the correct answer.

About This Chapter: Sets, Relations and Functions

Paper

Paper 3: Quantitative Aptitude

Weightage

3-5 Marks

Key Topics

Sets, Relations, Functions

This chapter covers Sets, Relations, Functions and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 3-5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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