Sets, Relations and FunctionsMCQPYQ Sep 24Question 1973 of 217
All Questions

If f(x)=x2+x1\displaystyle f(x) = x^2+x-1 and 4f(x)=f(2x)\displaystyle 4f(x) = f(2x), then find the value of 'x'.

Options

A2/3\displaystyle 2/3
B3/2\displaystyle 3/2
C3/4\displaystyle 3/4
D4/3\displaystyle 4/3
For any discrepancies in this question, email contact@cadada.in

Correct Answer

Option b3/2\displaystyle 3/2

All Options:

  • A2/3\displaystyle 2/3
  • B3/2\displaystyle 3/2
  • C3/4\displaystyle 3/4
  • D4/3\displaystyle 4/3

Ad

Detailed Solution & Explanation

Given:
f(x)=x2+x1f(x) = x^2 + x - 1
We are given the equation:
4f(x)=f(2x)4f(x) = f(2x)

**Step 1: Compute 4f(x)\displaystyle 4f(x)**
4f(x)=4(x2+x1)=4x2+4x44f(x) = 4(x^2 + x - 1) = 4x^2 + 4x - 4

**Step 2: Compute f(2x)\displaystyle f(2x)**
f(2x)=(2x)2+(2x)1=4x2+2x1f(2x) = (2x)^2 + (2x) - 1 = 4x^2 + 2x - 1

**Step 3: Equate the two expressions and solve for x\displaystyle x**
4x2+4x4=4x2+2x14x^2 + 4x - 4 = 4x^2 + 2x - 1
Subtract 4x2\displaystyle 4x^2 from both sides:
4x4=2x14x - 4 = 2x - 1
Subtract 2x\displaystyle 2x from both sides:
2x4=12x - 4 = -1
Add 4\displaystyle 4 to both sides:
2x=32x = 3
x=32x = \frac{3}{2}

Hence, **Option B** is the correct answer.

About This Chapter: Sets, Relations and Functions

Paper

Paper 3: Quantitative Aptitude

Weightage

3-5 Marks

Key Topics

Sets, Relations, Functions

This chapter covers Sets, Relations, Functions and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 3-5 Marks weightage. Focus on understanding core concepts rather than memorizing.

Related Comparison Tables

More Questions from Sets, Relations and Functions

Ready to Master Sets, Relations and Functions?

Practice all 217 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free