Sets, Relations and FunctionsMCQMTP May 20Question 1928 of 217
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A town has a total population of 50,000. Out of it 28,000 read the newspaper X and 23,000 read Y while 4,000 read both the papers. The number of persons not reading X and Y both is

Options

A2,000
B3,000
C2,500
Dnone of these
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Correct Answer

Option b3,000

All Options:

  • A2,000
  • B3,000
  • C2,500
  • Dnone of these

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Detailed Solution & Explanation

Let U\displaystyle U be the universal set representing the total population of the town, so N(U)=50,000\displaystyle N(U) = 50,000.
Let X\displaystyle X be the set of people who read newspaper X, so N(X)=28,000\displaystyle N(X) = 28,000.
Let Y\displaystyle Y be the set of people who read newspaper Y, so N(Y)=23,000\displaystyle N(Y) = 23,000.
The number of people who read both newspapers is given by N(XY)=4,000\displaystyle N(X \cap Y) = 4,000.
Using the principle of inclusion-exclusion, the number of people who read at least one of the two newspapers is:
N(XY)=N(X)+N(Y)N(XY)N(X \cup Y) = N(X) + N(Y) - N(X \cap Y)
N(XY)=28,000+23,0004,000N(X \cup Y) = 28,000 + 23,000 - 4,000
N(XY)=47,000N(X \cup Y) = 47,000
The number of persons not reading both newspapers (which means they do not read either of the two papers) is:
N(XY)=N(U)N(XY)N(X' \cap Y') = N(U) - N(X \cup Y)
N(XY)=50,00047,000=3,000N(X' \cap Y') = 50,000 - 47,000 = 3,000
Hence, **Option B** is the correct answer.

About This Chapter: Sets, Relations and Functions

Paper

Paper 3: Quantitative Aptitude

Weightage

3-5 Marks

Key Topics

Sets, Relations, Functions

This chapter covers Sets, Relations, Functions and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 3-5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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