Set, Relations and FunctionsMTP Oct 21Question 1989 of 217
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If f(x)=x2−1\displaystyle f(x)=x^2-1 and g(x)=x+12\displaystyle g(x)=\frac{x+1}{2}, then f(3)f(3)+g(3)\displaystyle \frac{f(3)}{f(3)+g(3)} is

Options

A5/4\displaystyle 5/4
B4/5\displaystyle 4/5
C3/5\displaystyle 3/5
D5/3\displaystyle 5/3
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Correct Answer

✅ Option b — 4/5\displaystyle 4/5

All Options:

  • A5/4\displaystyle 5/4
  • B4/5\displaystyle 4/5
  • C3/5\displaystyle 3/5
  • D5/3\displaystyle 5/3

Detailed Solution & Explanation

Given the functions:
f(x)=x2−1f(x) = x^2 - 1
g(x)=x+12g(x) = \frac{x + 1}{2}

**Step 1: Compute f(3)\displaystyle f(3)**
f(3)=32−1=9−1=8f(3) = 3^2 - 1 = 9 - 1 = 8

**Step 2: Compute g(3)\displaystyle g(3)**
g(3)=3+12=42=2g(3) = \frac{3 + 1}{2} = \frac{4}{2} = 2

**Step 3: Evaluate the expression f(3)f(3)+g(3)\displaystyle \frac{f(3)}{f(3) + g(3)}**
f(3)f(3)+g(3)=88+2=810=45\frac{f(3)}{f(3) + g(3)} = \frac{8}{8 + 2} = \frac{8}{10} = \frac{4}{5}

Hence, **Option B** is the correct answer.

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