Sets, Relations and FunctionsMCQMTP June 24 Series IIQuestion 2003 of 217
All Questions

Let R is the set of real numbers such that the function f:RR\displaystyle f: R \to R and g:RR\displaystyle g: R \to R are defined by f(x)=x2+3x+1\displaystyle f(x)=x^2+3x+1 and g(x)=2x3\displaystyle g(x)=2x-3 Find (fog):\displaystyle (fog):

Options

A4x2+6x+1\displaystyle 4x^2+6x+1
Bx2+6x+1\displaystyle x^2+6x+1
C4x26x+1\displaystyle 4x^2-6x+1
Dx26x+1\displaystyle x^2-6x+1
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Correct Answer

Option c4x26x+1\displaystyle 4x^2-6x+1

All Options:

  • A4x2+6x+1\displaystyle 4x^2+6x+1
  • Bx2+6x+1\displaystyle x^2+6x+1
  • C4x26x+1\displaystyle 4x^2-6x+1
  • Dx26x+1\displaystyle x^2-6x+1

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Detailed Solution & Explanation

To find the composite function (fg)(x)=f(g(x))\displaystyle (f \circ g)(x) = f(g(x)), we substitute the expression for g(x)\displaystyle g(x) into f(x)\displaystyle f(x):
Given:
f(x)=x2+3x+1f(x) = x^2 + 3x + 1
g(x)=2x3g(x) = 2x - 3

Substitute g(x)\displaystyle g(x) in place of x\displaystyle x in f(x)\displaystyle f(x):
f(g(x))=(2x3)2+3(2x3)+1f(g(x)) = (2x - 3)^2 + 3(2x - 3) + 1

**Step 1: Expand (2x3)2\displaystyle (2x - 3)^2**:
(2x3)2=4x212x+9(2x - 3)^2 = 4x^2 - 12x + 9

**Step 2: Expand 3(2x3)\displaystyle 3(2x - 3)**:
3(2x3)=6x93(2x - 3) = 6x - 9

**Step 3: Combine and simplify all terms**:
f(g(x))=(4x212x+9)+(6x9)+1f(g(x)) = (4x^2 - 12x + 9) + (6x - 9) + 1
f(g(x))=4x2+(12x+6x)+(99+1)f(g(x)) = 4x^2 + (-12x + 6x) + (9 - 9 + 1)
f(g(x))=4x26x+1f(g(x)) = 4x^2 - 6x + 1

Hence, **Option C** is the correct answer.

About This Chapter: Sets, Relations and Functions

Paper

Paper 3: Quantitative Aptitude

Weightage

3-5 Marks

Key Topics

Sets, Relations, Functions

This chapter covers Sets, Relations, Functions and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 3-5 Marks weightage. Focus on understanding core concepts rather than memorizing.

Key Concepts to Understand

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