Set, Relations and FunctionsMTP Jun 24Question 2005 of 136
All Questions

Find fg\displaystyle f \circ g for the functions f(x)=x8,g(x)=2x2+1\displaystyle f(x)=x^8, g(x)=2x^2+1

Options

Ax8(2x2+1)\displaystyle x^8(2x^2+1)
Bx8\displaystyle x^8
C2x2+1\displaystyle 2x^2+1
D(2x2+1)8\displaystyle (2x^2+1)^8
For any discrepancies in this question, email contact@cadada.in

Correct Answer

Option d(2x2+1)8\displaystyle (2x^2+1)^8

All Options:

  • Ax8(2x2+1)\displaystyle x^8(2x^2+1)
  • Bx8\displaystyle x^8
  • C2x2+1\displaystyle 2x^2+1
  • D(2x2+1)8\displaystyle (2x^2+1)^8

More Questions from Set, Relations and Functions

Ready to Master Set, Relations and Functions?

Practice all 136 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free