Set, Relations and FunctionsMTP June 24 Series IIIQuestion 2005 of 217
All Questions

Find f∘g\displaystyle f \circ g for the functions f(x)=x8,g(x)=2x2+1\displaystyle f(x)=x^8, g(x)=2x^2+1

Options

Ax8(2x2+1)\displaystyle x^8(2x^2+1)
Bx8\displaystyle x^8
C2x2+1\displaystyle 2x^2+1
D(2x2+1)8\displaystyle (2x^2+1)^8
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Correct Answer

✅ Option d — (2x2+1)8\displaystyle (2x^2+1)^8

All Options:

  • Ax8(2x2+1)\displaystyle x^8(2x^2+1)
  • Bx8\displaystyle x^8
  • C2x2+1\displaystyle 2x^2+1
  • D(2x2+1)8\displaystyle (2x^2+1)^8

Detailed Solution & Explanation

To find the composite function (f∘g)(x)=f(g(x))\displaystyle (f \circ g)(x) = f(g(x)), we substitute the function g(x)\displaystyle g(x) in place of x\displaystyle x in f(x)\displaystyle f(x):
Given:
f(x)=x8f(x) = x^8
g(x)=2x2+1g(x) = 2x^2 + 1

Substitute g(x)\displaystyle g(x) into f(x)\displaystyle f(x):
f(g(x))=(g(x))8f(g(x)) = (g(x))^8
Substitute g(x)=2x2+1\displaystyle g(x) = 2x^2 + 1:
f(g(x))=(2x2+1)8f(g(x)) = (2x^2 + 1)^8

Hence, **Option D** is the correct answer.

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