Number Series, Coding, Odd Man OutPYQ Nov 20Question 2016 of 217
All Questions

Find the wrong term in: G4T, J10R, M20P, P43N, S90L.

Options

AM20P
BP43N
CJ10R
DG4T
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Correct Answer

✅ Option c — J10R

All Options:

  • AM20P
  • BP43N
  • CJ10R
  • DG4T

Detailed Solution & Explanation

We are given the alphanumeric series: G4T, J10R, M20P, P43N, S90L.
Let's analyze each component of the terms separately:
1. **First Letter:** G, J, M, P, S
- Alphabetic positions: G (7), J (10), M (13), P (16), S (19).
- Pattern: +3\displaystyle +3 position shift each time. This pattern is correct for all terms.
2. **Last Letter:** T, R, P, N, L
- Alphabetic positions: T (20), R (18), P (16), N (14), L (12).
- Pattern: −2\displaystyle -2 position shift each time. This pattern is correct for all terms.
3. **Middle Number:** 4, 10, 20, 43, 90
- Let's analyze the recurrence relation for the numbers:
xn=2xn−1+(n−1)for n≥2x_n = 2 x_{n-1} + (n-1) \quad \text{for } n \ge 2
- x1=4\displaystyle x_1 = 4
- x2=2x1+1=2(4)+1=9\displaystyle x_2 = 2 x_1 + 1 = 2(4) + 1 = 9
- x3=2x2+2=2(9)+2=20\displaystyle x_3 = 2 x_2 + 2 = 2(9) + 2 = 20
- x4=2x3+3=2(20)+3=43\displaystyle x_4 = 2 x_3 + 3 = 2(20) + 3 = 43
- x5=2x4+4=2(43)+4=90\displaystyle x_5 = 2 x_4 + 4 = 2(43) + 4 = 90
- Applying the logic, the second term should have the number 9\displaystyle 9 instead of 10\displaystyle 10 (giving G4T →\displaystyle \to J9R →\displaystyle \to M20P →\displaystyle \to \text{Rs. }43N →\displaystyle \to S90L).
- Therefore, J10R is the incorrect/wrong term in the series.
Hence, **Option C** is the correct answer.

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