Number Series, Coding and DecodingMCQPYQ Jan 21Question 2019 of 217
All Questions

Find the missing term: P3C, R5E, T8I, V12L, ?

Options

AY17O
BX17M
CX17O
DX16O
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option c — X17O

All Options:

  • AY17O
  • BX17M
  • CX17O
  • DX16O

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Detailed Solution & Explanation

We are given the alphanumeric series: P3C, R5E, T8I, V12L, ?
Let's analyze each component of the terms:
1. **First Letter:** P, R, T, V
- Alphabetic positions: P (16), R (18), T (20), V (22).
- Pattern: +2\displaystyle +2 position shift each time. The next letter position is 22+2=24\displaystyle 22 + 2 = 24, which is **X**.
2. **Middle Number:** 3, 5, 8, 12
- Differences: 5−3=2\displaystyle 5 - 3 = 2, 8−5=3\displaystyle 8 - 5 = 3, 12−8=4\displaystyle 12 - 8 = 4.
- The differences increase by 1\displaystyle 1 each time (+2,+3,+4\displaystyle +2, +3, +4).
- The next difference is +5\displaystyle +5. The next number is 12+5=17\displaystyle 12 + 5 = 17.
3. **Last Letter:** C, E, I, L
- **Discrepancy Note:** The standard version of this question uses the sequence C, F, I, L, where the alphabetic positions are C (3), F (6), I (9), L (12), which increases by +3\displaystyle +3 each time. The term "R5E" in the question text is a misprint of "R5F". Using the standard +3\displaystyle +3 pattern, the next letter position is 12+3=15\displaystyle 12 + 3 = 15, which corresponds to the letter **O**.
Combining the parts: X + 17 + O = **X17O**.
Hence, **Option C** is the correct answer.

About This Chapter: Number Series, Coding and Decoding

Paper

Paper 3: Quantitative Aptitude

Weightage

5 Marks

Key Topics

Number series, Coding & Decoding, Odd man out

This chapter covers Number series, Coding & Decoding, Odd man out and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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