Number Series, Coding and DecodingMCQMTP Oct 21Question 2056 of 217
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Find next term of the series 3,10,29,66,127,?\displaystyle 3, 10, 29, 66, 127, ?

Options

A164\displaystyle 164
B187\displaystyle 187
C216\displaystyle 216
D218\displaystyle 218
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Correct Answer

Option d218\displaystyle 218

All Options:

  • A164\displaystyle 164
  • B187\displaystyle 187
  • C216\displaystyle 216
  • D218\displaystyle 218

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Detailed Solution & Explanation

We are given the series: 3,10,29,66,127,\displaystyle 3, 10, 29, 66, 127, \dots
Let's express each term in relation to perfect cubes:
- 3=13+2\displaystyle 3 = 1^3 + 2
- 10=23+2\displaystyle 10 = 2^3 + 2
- 29=33+2\displaystyle 29 = 3^3 + 2
- 66=43+2\displaystyle 66 = 4^3 + 2
- 127=53+2\displaystyle 127 = 5^3 + 2
The series is of the form n3+2\displaystyle n^3 + 2 for consecutive natural numbers n\displaystyle n.
The next term must be 63+2\displaystyle 6^3 + 2:
63+2=216+2=2186^3 + 2 = 216 + 2 = 218
Hence, **Option D** is the correct answer.

About This Chapter: Number Series, Coding and Decoding

Paper

Paper 3: Quantitative Aptitude

Weightage

5 Marks

Key Topics

Number series, Coding & Decoding, Odd man out

This chapter covers Number series, Coding & Decoding, Odd man out and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

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Exam Strategy Tip

This topic carries 5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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