In a code, MENTION is written as LNEITNO. How is PRESENT written in that code?
Options
ANTSEREO
BOERESTN
CERESTNO
DROESTNE
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Number Series, Coding and DecodingMCQPYQ Dec 21Question 2096 of 217
All Questions Correct Answer
✅ Option b — OERESTN
All Options:
- ANTSEREO
- BOERESTN
- CERESTNO
- DROESTNE
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Detailed Solution & Explanation
To find how the word **PRESENT** is written in the given code:
Let us analyze the coding rule by studying how **MENTION** becomes **LNEITNO**:
1. **First Letter Rule:**
The first letter **M** is shifted backward by position in the alphabet:
2. **Remaining Letters Rule:**
The remaining letters of **MENTION** are **E, N, T, I, O, N**. We divide them into consecutive pairs and reverse each pair:
- Pair 1:
- Pair 2:
- Pair 3:
Concatenating these reversed pairs gives **NEITNO**.
Combining both parts, we get **L** + **NEITNO** .
Now we apply this exact same rule to the word **PRESENT**:
1. **First Letter Rule:**
The first letter **P** is shifted backward by position:
2. **Remaining Letters Rule:**
The remaining letters of **PRESENT** are **R, E, S, E, N, T**. We divide them into consecutive pairs and reverse each pair:
- Pair 1:
- Pair 2:
- Pair 3:
Concatenating these reversed pairs gives **ERESTN**.
Combining both parts, we get **O** + **ERESTN** .
Hence, **Option B** is the correct answer.
Let us analyze the coding rule by studying how **MENTION** becomes **LNEITNO**:
1. **First Letter Rule:**
The first letter **M** is shifted backward by position in the alphabet:
2. **Remaining Letters Rule:**
The remaining letters of **MENTION** are **E, N, T, I, O, N**. We divide them into consecutive pairs and reverse each pair:
- Pair 1:
- Pair 2:
- Pair 3:
Concatenating these reversed pairs gives **NEITNO**.
Combining both parts, we get **L** + **NEITNO** .
Now we apply this exact same rule to the word **PRESENT**:
1. **First Letter Rule:**
The first letter **P** is shifted backward by position:
2. **Remaining Letters Rule:**
The remaining letters of **PRESENT** are **R, E, S, E, N, T**. We divide them into consecutive pairs and reverse each pair:
- Pair 1:
- Pair 2:
- Pair 3:
Concatenating these reversed pairs gives **ERESTN**.
Combining both parts, we get **O** + **ERESTN** .
Hence, **Option B** is the correct answer.
About This Chapter: Number Series, Coding and Decoding
Paper
Paper 3: Quantitative Aptitude
Weightage
5 Marks
Key Topics
Number series, Coding & Decoding, Odd man out
This chapter covers Number series, Coding & Decoding, Odd man out and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.
View Official ICAI SyllabusExam Strategy Tip
This topic carries 5 Marks weightage. Focus on understanding core concepts rather than memorizing.
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