Number Series, Coding, Odd Man OutPYQ Jun 23Question 2103 of 217
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In a certain code SIKKIM is written as THLJLIL then how is TRAINING written in that code?

Options

ASQBHOHOH
BUQBHOHOF
CUQBOJOHOH
DUQBOJOHOF
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Correct Answer

✅ Option b — UQBHOHOF

All Options:

  • ASQBHOHOH
  • BUQBHOHOF
  • CUQBOJOHOH
  • DUQBOJOHOF

Detailed Solution & Explanation

To find how the word **TRAINING** is written in the given code, let us analyze the pattern by studying the transformation of **SIKKIM** into **THLJLIL**:

Let us calculate the alphabetical shifts for each letter position (where A=1,B=2,…,Z=26\displaystyle A = 1, B = 2, \dots, Z = 26):
- S (19)→T (20)  ⟹  Shift of +1\displaystyle S\ (19) \to T\ (20) \implies \text{Shift of } +1
- I (9)→H (8)  ⟹  Shift of −1\displaystyle I\ (9) \to H\ (8) \implies \text{Shift of } -1
- K (11)→L (12)  ⟹  Shift of +1\displaystyle K\ (11) \to L\ (12) \implies \text{Shift of } +1
- K (11)→J (10)  ⟹  Shift of −1\displaystyle K\ (11) \to J\ (10) \implies \text{Shift of } -1
- I (9)→J (10)  ⟹  Shift of +1\displaystyle I\ (9) \to J\ (10) \implies \text{Shift of } +1
- M (13)→L (12)  ⟹  Shift of −1\displaystyle M\ (13) \to L\ (12) \implies \text{Shift of } -1

We observe a clear, alternating pattern of shifting +1\displaystyle +1 and −1\displaystyle -1 for successive letters. We apply this exact pattern to the word **TRAINING**:
- T (20)+1=21  ⟹  U\displaystyle T\ (20) + 1 = 21 \implies \mathbf{U}
- R (18)−1=17  ⟹  Q\displaystyle R\ (18) - 1 = 17 \implies \mathbf{Q}
- A (1)+1=2  ⟹  B\displaystyle A\ (1) + 1 = 2 \implies \mathbf{B}
- I (9)−1=8  ⟹  H\displaystyle I\ (9) - 1 = 8 \implies \mathbf{H}
- N (14)+1=15  ⟹  O\displaystyle N\ (14) + 1 = 15 \implies \mathbf{O}
- I (9)−1=8  ⟹  H\displaystyle I\ (9) - 1 = 8 \implies \mathbf{H}
- N (14)+1=15  ⟹  O\displaystyle N\ (14) + 1 = 15 \implies \mathbf{O}
- G (7)−1=6  ⟹  F\displaystyle G\ (7) - 1 = 6 \implies \mathbf{F}

Putting the coded letters in sequence, the code for **TRAINING** is **UQBHOHOF**.

Hence, **Option B** is the correct answer.

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