Number Series, Coding, Odd Man OutMTP Nov 18Question 2111 of 217
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In a certain code language 'EXAM' is coded as 39 'PAPER' is coded at 51 then PASS is coded as

Options

A39
B47
C489
D51
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Correct Answer

✅ Option d — 51

All Options:

  • A39
  • B47
  • C489
  • D51

Detailed Solution & Explanation

Let's determine the coding rule using the alphabetical positions (A=1,B=2,…,Z=26\displaystyle A=1, B=2, \dots, Z=26):
1. For the word EXAM\displaystyle EXAM (number of letters, n=4\displaystyle n = 4):
Alphabetical values: E=5\displaystyle E = 5, X=24\displaystyle X = 24, A=1\displaystyle A = 1, M=13\displaystyle M = 13
Sum of values = 5+24+1+13=43\displaystyle 5 + 24 + 1 + 13 = 43
Subtracting the number of letters: Code=43−4=39\displaystyle \text{Code} = 43 - 4 = 39.

2. For the word PAPER\displaystyle PAPER (number of letters, n=5\displaystyle n = 5):
Alphabetical values: P=16\displaystyle P = 16, A=1\displaystyle A = 1, P=16\displaystyle P = 16, E=5\displaystyle E = 5, R=18\displaystyle R = 18
Sum of values = 16+1+16+5+18=56\displaystyle 16 + 1 + 16 + 5 + 18 = 56
Subtracting the number of letters: Code=56−5=51\displaystyle \text{Code} = 56 - 5 = 51.

From these examples, the rule is:
Code=∑(alphabetical positions)−n\text{Code} = \sum (\text{alphabetical positions}) - n where n\displaystyle n is the number of letters in the word.

Now, let's find the code for PASS\displaystyle PASS (n=4\displaystyle n = 4):
Alphabetical values: P=16\displaystyle P = 16, A=1\displaystyle A = 1, S=19\displaystyle S = 19, S=19\displaystyle S = 19
Sum of values = 16+1+19+19=55\displaystyle 16 + 1 + 19 + 19 = 55
Subtracting the number of letters: Code=55−4=51\displaystyle \text{Code} = 55 - 4 = 51.

Hence, **Option D** is the correct answer.

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