Number Series, Coding and DecodingMCQMTP March 22Question 2129 of 217
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If E=5\displaystyle E = 5 and READ=7\displaystyle READ = 7, then what is the code of 'DEAR'?

Options

A6
B7
C8
D9
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Correct Answer

✅ Option b — 7

All Options:

  • A6
  • B7
  • C8
  • D9

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Detailed Solution & Explanation

Let's find the coding rule using standard alphabetical positions (A=1,B=2,…,Z=26\displaystyle A=1, B=2, \dots, Z=26):
1. For the letter E\displaystyle E, the position is 5\displaystyle 5. The code is 5\displaystyle 5. Since there is 1\displaystyle 1 letter, the average position is 5/1=5\displaystyle 5/1 = 5.
2. For the word READ\displaystyle READ (number of letters, n=4\displaystyle n = 4):
Alphabetical values: R=18\displaystyle R = 18, E=5\displaystyle E = 5, A=1\displaystyle A = 1, D=4\displaystyle D = 4
Sum of values = 18+5+1+4=28\displaystyle 18 + 5 + 1 + 4 = 28
Calculating the average position:
Code=Sum of positionsn=284=7\text{Code} = \frac{\text{Sum of positions}}{n} = \frac{28}{4} = 7 This matches the given code.

Now, let's apply the same rule to the word DEAR\displaystyle DEAR (which consists of the exact same letters as READ\displaystyle READ in a different order):
Alphabetical values: D=4\displaystyle D = 4, E=5\displaystyle E = 5, A=1\displaystyle A = 1, R=18\displaystyle R = 18
Sum of values = 4+5+1+18=28\displaystyle 4 + 5 + 1 + 18 = 28
Calculating the average position:
Code=Sum of positionsn=284=7\text{Code} = \frac{\text{Sum of positions}}{n} = \frac{28}{4} = 7

Hence, **Option B** is the correct answer.

About This Chapter: Number Series, Coding and Decoding

Paper

Paper 3: Quantitative Aptitude

Weightage

5 Marks

Key Topics

Number series, Coding & Decoding, Odd man out

This chapter covers Number series, Coding & Decoding, Odd man out and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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