Number Series, Coding, Odd Man OutMTP Dec 22 - Series I/ MTP Sep 24Question 2132 of 217
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In a code, TEACHER is written as VGCEJGT. How is CHILDREN written in that code?

Options

AEJKNEGTP
BEJKNFGTP
CEJRNFGTO
DEJKNFETP
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Correct Answer

✅ Option b — EJKNFGTP

All Options:

  • AEJKNEGTP
  • BEJKNFGTP
  • CEJRNFGTO
  • DEJKNFETP

Detailed Solution & Explanation

Let's identify the shift pattern in the coding of TEACHER→VGCEJGT\displaystyle TEACHER \rightarrow VGCEJGT by examining the alphabetical positions:
- T (20)→+2V (22)\displaystyle \text{T (20)} \xrightarrow{+2} \text{V (22)}
- E (5)→+2G (7)\displaystyle \text{E (5)} \xrightarrow{+2} \text{G (7)}
- A (1)→+2C (3)\displaystyle \text{A (1)} \xrightarrow{+2} \text{C (3)}
- C (3)→+2E (5)\displaystyle \text{C (3)} \xrightarrow{+2} \text{E (5)}
- H (8)→+2J (10)\displaystyle \text{H (8)} \xrightarrow{+2} \text{J (10)}
- E (5)→+2G (7)\displaystyle \text{E (5)} \xrightarrow{+2} \text{G (7)}
- R (18)→+2T (20)\displaystyle \text{R (18)} \xrightarrow{+2} \text{T (20)}

The pattern is a constant forward shift of +2\displaystyle +2 for each letter.

Now, let's apply the +2\displaystyle +2 shift to the word CHILDREN\displaystyle CHILDREN:
1. C (3)→+2E (5)\displaystyle \text{C (3)} \xrightarrow{+2} \text{E (5)}
2. H (8)→+2J (10)\displaystyle \text{H (8)} \xrightarrow{+2} \text{J (10)}
3. I (9)→+2K (11)\displaystyle \text{I (9)} \xrightarrow{+2} \text{K (11)}
4. L (12)→+2N (14)\displaystyle \text{L (12)} \xrightarrow{+2} \text{N (14)}
5. D (4)→+2F (6)\displaystyle \text{D (4)} \xrightarrow{+2} \text{F (6)}
6. R (18)→+2T (20)\displaystyle \text{R (18)} \xrightarrow{+2} \text{T (20)}
7. E (5)→+2G (7)\displaystyle \text{E (5)} \xrightarrow{+2} \text{G (7)}
8. N (14)→+2P (16)\displaystyle \text{N (14)} \xrightarrow{+2} \text{P (16)}

Combining these letters, we get the code EJKNFGTP\displaystyle EJKNFGTP.

Hence, **Option B** is the correct answer.

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