Number Series, Coding and DecodingMCQMTP Dec 2023 Series IIQuestion 2145 of 217
All Questions

If A=2\displaystyle A = 2, M=26\displaystyle M = 26, Z=52\displaystyle Z = 52, then BET = ?

Options

A44
B54
C64
D72
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Correct Answer

Option b54

All Options:

  • A44
  • B54
  • C64
  • D72

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Detailed Solution & Explanation

Let's identify the relationship between the letters and numbers by checking their standard alphabetical positions (A=1,B=2,,Z=26\displaystyle A=1, B=2, \dots, Z=26):
1. For the letter A\displaystyle A: Position=1    Code=2×1=2\displaystyle \text{Position} = 1 \implies \text{Code} = 2 \times 1 = 2
2. For the letter M\displaystyle M: Position=13    Code=2×13=26\displaystyle \text{Position} = 13 \implies \text{Code} = 2 \times 13 = 26
3. For the letter Z\displaystyle Z: Position=26    Code=2×26=52\displaystyle \text{Position} = 26 \implies \text{Code} = 2 \times 26 = 52

The rule is: Code=2×Alphabetical Position\displaystyle \text{Code} = 2 \times \text{Alphabetical Position}.

Now, let's apply this rule to the word BET\displaystyle BET:
- B=2    Value=2×2=4\displaystyle \text{B} = 2 \implies \text{Value} = 2 \times 2 = 4
- E=5    Value=2×5=10\displaystyle \text{E} = 5 \implies \text{Value} = 2 \times 5 = 10
- T=20    Value=2×20=40\displaystyle \text{T} = 20 \implies \text{Value} = 2 \times 20 = 40

Summing these coded values:
Sum=4+10+40=54\text{Sum} = 4 + 10 + 40 = 54

Hence, **Option B** is the correct answer.

About This Chapter: Number Series, Coding and Decoding

Paper

Paper 3: Quantitative Aptitude

Weightage

5 Marks

Key Topics

Number series, Coding & Decoding, Odd man out

This chapter covers Number series, Coding & Decoding, Odd man out and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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