Number Series, Coding and DecodingMCQMTP June 24 Series IQuestion 2147 of 217
All Questions

If MACHINE is coded as 19−7−9−14−15−20−11\displaystyle 19 - 7 - 9 - 14 - 15 - 20 - 11, how will you code DANGER?

Options

A11−7−20−16−11−24\displaystyle 11 - 7 - 20 - 16 - 11 - 24
B13−7−20−9−11−25\displaystyle 13 - 7 - 20 - 9 - 11 - 25
C10−7−20−13−11−24\displaystyle 10 - 7 - 20 - 13 - 11 - 24
D13−7−20−10−11−25\displaystyle 13 - 7 - 20 - 10 - 11 - 25
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Correct Answer

✅ Option c — 10−7−20−13−11−24\displaystyle 10 - 7 - 20 - 13 - 11 - 24

All Options:

  • A11−7−20−16−11−24\displaystyle 11 - 7 - 20 - 16 - 11 - 24
  • B13−7−20−9−11−25\displaystyle 13 - 7 - 20 - 9 - 11 - 25
  • C10−7−20−13−11−24\displaystyle 10 - 7 - 20 - 13 - 11 - 24
  • D13−7−20−10−11−25\displaystyle 13 - 7 - 20 - 10 - 11 - 25

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Detailed Solution & Explanation

Let's analyze the coding pattern by comparing alphabetical positions of the letters in MACHINE\displaystyle MACHINE with their given codes:
- M (13)→13+6=19\displaystyle \text{M (13)} \rightarrow 13 + 6 = 19
- A (1)→1+6=7\displaystyle \text{A (1)} \rightarrow 1 + 6 = 7
- C (3)→3+6=9\displaystyle \text{C (3)} \rightarrow 3 + 6 = 9
- H (8)→8+6=14\displaystyle \text{H (8)} \rightarrow 8 + 6 = 14
- I (9)→9+6=15\displaystyle \text{I (9)} \rightarrow 9 + 6 = 15
- N (14)→14+6=20\displaystyle \text{N (14)} \rightarrow 14 + 6 = 20
- E (5)→5+6=11\displaystyle \text{E (5)} \rightarrow 5 + 6 = 11

The coding rule is to add +6\displaystyle +6 to the alphabetical position of each letter.

Now, let's apply this rule to the word DANGER\displaystyle DANGER:
1. D (4)→4+6=10\displaystyle \text{D (4)} \rightarrow 4 + 6 = 10
2. A (1)→1+6=7\displaystyle \text{A (1)} \rightarrow 1 + 6 = 7
3. N (14)→14+6=20\displaystyle \text{N (14)} \rightarrow 14 + 6 = 20
4. G (7)→7+6=13\displaystyle \text{G (7)} \rightarrow 7 + 6 = 13
5. E (5)→5+6=11\displaystyle \text{E (5)} \rightarrow 5 + 6 = 11
6. R (18)→18+6=24\displaystyle \text{R (18)} \rightarrow 18 + 6 = 24

Combining these digits with hyphens, we get: 10−7−20−13−11−24\displaystyle 10 - 7 - 20 - 13 - 11 - 24.

Hence, **Option C** is the correct answer.

About This Chapter: Number Series, Coding and Decoding

Paper

Paper 3: Quantitative Aptitude

Weightage

5 Marks

Key Topics

Number series, Coding & Decoding, Odd man out

This chapter covers Number series, Coding & Decoding, Odd man out and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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