Number Series, Coding and DecodingMCQPYQ Jun 23Question 2171 of 217
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Find the odd man out in the following series: 190,145,136,352,460,324,631,244\displaystyle 190, 145, 136, 352, 460, 324, 631, 244.

Options

A136
B244
C460
D324
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Correct Answer

Option d324

All Options:

  • A136
  • B244
  • C460
  • D324

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Detailed Solution & Explanation

Let's calculate the sum of the digits for each number in the series:
- 190    1+9+0=10\displaystyle 190 \implies 1 + 9 + 0 = 10
- 145    1+4+5=10\displaystyle 145 \implies 1 + 4 + 5 = 10
- 136    1+3+6=10\displaystyle 136 \implies 1 + 3 + 6 = 10
- 352    3+5+2=10\displaystyle 352 \implies 3 + 5 + 2 = 10
- 460    4+6+0=10\displaystyle 460 \implies 4 + 6 + 0 = 10
- 324    3+2+4=9\displaystyle 324 \implies 3 + 2 + 4 = 9
- 631    6+3+1=10\displaystyle 631 \implies 6 + 3 + 1 = 10
- 244    2+4+4=10\displaystyle 244 \implies 2 + 4 + 4 = 10

All the numbers in the series have a digit sum of 10\displaystyle 10, except 324\displaystyle 324, which has a digit sum of 9\displaystyle 9. Therefore, 324\displaystyle 324 is the odd man out.

Hence, **Option D** is the correct answer.

About This Chapter: Number Series, Coding and Decoding

Paper

Paper 3: Quantitative Aptitude

Weightage

5 Marks

Key Topics

Number series, Coding & Decoding, Odd man out

This chapter covers Number series, Coding & Decoding, Odd man out and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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