Number Series, Coding, Odd Man OutPYQ Jun 23Question 2171 of 217
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Find the odd man out in the following series: 190,145,136,352,460,324,631,244\displaystyle 190, 145, 136, 352, 460, 324, 631, 244.

Options

A136
B244
C460
D324
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Correct Answer

✅ Option d — 324

All Options:

  • A136
  • B244
  • C460
  • D324

Detailed Solution & Explanation

Let's calculate the sum of the digits for each number in the series:
- 190  ⟹  1+9+0=10\displaystyle 190 \implies 1 + 9 + 0 = 10
- 145  ⟹  1+4+5=10\displaystyle 145 \implies 1 + 4 + 5 = 10
- 136  ⟹  1+3+6=10\displaystyle 136 \implies 1 + 3 + 6 = 10
- 352  ⟹  3+5+2=10\displaystyle 352 \implies 3 + 5 + 2 = 10
- 460  ⟹  4+6+0=10\displaystyle 460 \implies 4 + 6 + 0 = 10
- 324  ⟹  3+2+4=9\displaystyle 324 \implies 3 + 2 + 4 = 9
- 631  ⟹  6+3+1=10\displaystyle 631 \implies 6 + 3 + 1 = 10
- 244  ⟹  2+4+4=10\displaystyle 244 \implies 2 + 4 + 4 = 10

All the numbers in the series have a digit sum of 10\displaystyle 10, except 324\displaystyle 324, which has a digit sum of 9\displaystyle 9. Therefore, 324\displaystyle 324 is the odd man out.

Hence, **Option D** is the correct answer.

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