Number Series, Coding, Odd Man OutMTP June 24 Series IIIQuestion 2195 of 217
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Find odd man out of the series 16,25,36,72,144,196,225\displaystyle 16, 25, 36, 72, 144, 196, 225

Options

A36\displaystyle 36
B72\displaystyle 72
C196\displaystyle 196
D225\displaystyle 225
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Correct Answer

✅ Option b — 72\displaystyle 72

All Options:

  • A36\displaystyle 36
  • B72\displaystyle 72
  • C196\displaystyle 196
  • D225\displaystyle 225

Detailed Solution & Explanation

To find the odd man out in the given series, we analyze the mathematical properties of each term in the sequence: 16,25,36,72,144,196,22516, 25, 36, 72, 144, 196, 225 Let us check if the numbers are perfect squares: 1. 16=42\displaystyle 16 = 4^2 (a perfect square of the integer 4\displaystyle 4) 2. 25=52\displaystyle 25 = 5^2 (a perfect square of the integer 5\displaystyle 5) 3. 36=62\displaystyle 36 = 6^2 (a perfect square of the integer 6\displaystyle 6) 4. 72\displaystyle 72 is not a perfect square of any integer (82=64\displaystyle 8^2 = 64 and 92=81\displaystyle 9^2 = 81) 5. 144=122\displaystyle 144 = 12^2 (a perfect square of the integer 12\displaystyle 12) 6. 196=142\displaystyle 196 = 14^2 (a perfect square of the integer 14\displaystyle 14) 7. 225=152\displaystyle 225 = 15^2 (a perfect square of the integer 15\displaystyle 15) All the terms in the series are perfect squares of integers except for 72\displaystyle 72. Therefore, 72\displaystyle 72 is the odd man out in this series. Hence, **Option B** is the correct answer.

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