ProbabilityMCQMTP May 20Question 2817 of 295
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The probability that an Accountant's job applicant has a B. Com. Degree is 0.85\displaystyle 0.85, that he is a CA is 0.30\displaystyle 0.30 and that he is both B. Com. and CA is 0.25\displaystyle 0.25 out of 500\displaystyle 500 applicants, how many would be B. Com. or CA?

Options

A0.25
B0.30
C0.10
D0.90
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Correct Answer

Option d0.90

All Options:

  • A0.25
  • B0.30
  • C0.10
  • D0.90

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Detailed Solution & Explanation

Let B\displaystyle B represent the event that an applicant has a B. Com. Degree, and C\displaystyle C represent the event that an applicant is a CA. 1. We are given the following probabilities: - P(B)=0.85\displaystyle P(B) = 0.85 - P(C)=0.30\displaystyle P(C) = 0.30 - P(BC)=0.25\displaystyle P(B \cap C) = 0.25 2. The probability that an applicant is a B. Com. or a CA is given by the addition theorem of probability: P(BC)=P(B)+P(C)P(BC)P(B \cup C) = P(B) + P(C) - P(B \cap C) P(BC)=0.85+0.300.25=0.90P(B \cup C) = 0.85 + 0.30 - 0.25 = 0.90 3. Although the question asks "how many" out of 500 applicants (which would be 500×0.90=450\displaystyle 500 \times 0.90 = 450 applicants), the options provided correspond to the probability value of 0.90\displaystyle 0.90. 4. Thus, matching the options, the probability is 0.90\displaystyle 0.90, which corresponds to Option D. Hence, **Option D** is the correct answer.

About This Chapter: Probability

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Probability Operations, Expected Value

A logic-heavy chapter dealing with random experiments, events (mutually exclusive, exhaustive), set theory probability, conditional probability, and Bayes' Theorem. It forms the basis for Theoretical Distributions.

View Official ICAI Syllabus

Exam Strategy Tip

Always draw a quick Venn Diagram or tree when faced with 'At least one' or 'Only A but not B' wording. It saves you from double-counting.

Key Concepts to Understand

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