ProbabilityMCQPYQ Dec. 21Question 2838 of 295
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If two dice are rolled and one of the dice shows 1 at a point then how many such outcome can be done where it is known that its probability is 136\displaystyle \frac{1}{36} where X=\displaystyle X =

Options

A11\displaystyle 11
B7\displaystyle 7
C8\displaystyle 8
D9\displaystyle 9
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Correct Answer

Option a11\displaystyle 11

All Options:

  • A11\displaystyle 11
  • B7\displaystyle 7
  • C8\displaystyle 8
  • D9\displaystyle 9

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Detailed Solution & Explanation

When two fair six-sided dice are rolled, the sample space consists of 6×6=36\displaystyle 6 \times 6 = 36 equally likely outcomes. We want to find how many outcomes contain at least one die showing the number 1. Let's list these outcomes: - First die shows 1: (1,1), (1,2), (1,3), (1,4), (1,5), (1,6) (6 outcomes) - Second die shows 1: (2,1), (3,1), (4,1), (5,1), (6,1) (5 outcomes, excluding (1,1) since it is already counted) Combining these, there are: 6+5=11\displaystyle 6 + 5 = 11 such outcomes. Since each outcome in the sample space has a probability of 136\displaystyle \frac{1}{36}, there are exactly 11 outcomes matching this condition. Hence, **Option A** is the correct answer.

About This Chapter: Probability

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Probability Operations, Expected Value

A logic-heavy chapter dealing with random experiments, events (mutually exclusive, exhaustive), set theory probability, conditional probability, and Bayes' Theorem. It forms the basis for Theoretical Distributions.

View Official ICAI Syllabus

Exam Strategy Tip

Always draw a quick Venn Diagram or tree when faced with 'At least one' or 'Only A but not B' wording. It saves you from double-counting.

Key Concepts to Understand

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