Central Tendency & DispersionPYQ Nov 18Question 2857 of 473
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The algebraic sum of the deviation of a set of values from their arithmetic mean is

Options

A>0\displaystyle >0
B=0\displaystyle =0
C<0\displaystyle <0
DNone of these
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Correct Answer

✅ Option b — =0\displaystyle =0

All Options:

  • A>0\displaystyle >0
  • B=0\displaystyle =0
  • C<0\displaystyle <0
  • DNone of these

Detailed Solution & Explanation

**Step 1: Define algebraic sum of deviations.** Let x1,x2,…,xn\displaystyle x_1, x_2, \ldots, x_n be observations with arithmetic mean xˉ\displaystyle \bar{x}. Algebraic sum of deviations =∑i=1n(xi−xˉ)\displaystyle = \sum_{i=1}^{n}(x_i - \bar{x}) **Step 2: Expand the sum.** ∑i=1n(xi−xˉ)=∑i=1nxi−nxˉ\sum_{i=1}^{n}(x_i - \bar{x}) = \sum_{i=1}^{n} x_i - n\bar{x} **Step 3: Substitute xˉ=∑xin\displaystyle \bar{x} = \frac{\sum x_i}{n}.** =∑xi−n⋅∑xin=∑xi−∑xi=0= \sum x_i - n \cdot \frac{\sum x_i}{n} = \sum x_i - \sum x_i = 0 **Conclusion:** The algebraic sum of deviations from the arithmetic mean is always **zero**. Hence, **Option B** is the correct answer.

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