Central Tendency & DispersionPYQ June 19Question 2861 of 473
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The AM of 15 observation is 9 and the AM of first 9 observation is 11 and then AM of remaining observation is

Options

A11\displaystyle 11
B6\displaystyle 6
C3\displaystyle 3
D9\displaystyle 9
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Correct Answer

✅ Option b — 6\displaystyle 6

All Options:

  • A11\displaystyle 11
  • B6\displaystyle 6
  • C3\displaystyle 3
  • D9\displaystyle 9

Detailed Solution & Explanation

**Step 1: Find the total sum of all 15 observations.** Total sum=15×9=135\text{Total sum} = 15 \times 9 = 135 **Step 2: Find the sum of first 9 observations.** Sum of first 9=9×11=99\text{Sum of first 9} = 9 \times 11 = 99 **Step 3: Find the sum of remaining 6 observations.** Remaining observations =15−9=6\displaystyle = 15 - 9 = 6 Sum of remaining 6=135−99=36\text{Sum of remaining 6} = 135 - 99 = 36 **Step 4: Compute the AM of remaining observations.** AM of remaining=366=6\text{AM of remaining} = \frac{36}{6} = 6 Hence, **Option B** is the correct answer.

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