Measures of Central Tendency and DispersionMCQPYQ June 24Question 2877 of 473
All Questions

If there are two groups containing 40 and 30 observations and have arithmetic means as 50 and 60, then the combined arithmetic mean is

Options

A55.48
B56.35
C54.28
D50.28
For any discrepancies in this question, email contact@cadada.in

Correct Answer

Option c54.28

All Options:

  • A55.48
  • B56.35
  • C54.28
  • D50.28

Ad

Detailed Solution & Explanation

**Step 1: State the formula for combined mean.** xˉ12=n1xˉ1+n2xˉ2n1+n2\bar{x}_{12} = \frac{n_1 \bar{x}_1 + n_2 \bar{x}_2}{n_1 + n_2} **Step 2: Substitute values.** n1=40\displaystyle n_1 = 40, xˉ1=50\displaystyle \bar{x}_1 = 50, n2=30\displaystyle n_2 = 30, xˉ2=60\displaystyle \bar{x}_2 = 60. xˉ12=40×50+30×6040+30=2000+180070=380070=54.2857...54.28\bar{x}_{12} = \frac{40 \times 50 + 30 \times 60}{40 + 30} = \frac{2000 + 1800}{70} = \frac{3800}{70} = 54.2857... \approx 54.28 Hence, **Option C** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

Related Comparison Tables

More Questions from Measures of Central Tendency and Dispersion

Ready to Master Measures of Central Tendency and Dispersion?

Practice all 473 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free