Measures of Central Tendency and DispersionMCQMTP May 18Question 2886 of 473
All Questions

The mean of first 3 terms is 14 and the mean of next 2 terms is 18. The mean of 5 numbers is

Options

A14.5
B15
C14
D15.6
For any discrepancies in this question, email contact@cadada.in

Correct Answer

Option d15.6

All Options:

  • A14.5
  • B15
  • C14
  • D15.6

Ad

Detailed Solution & Explanation

**Step 1: Compute sum of first 3 terms.** Sum1=3×14=42\text{Sum}_1 = 3 \times 14 = 42 **Step 2: Compute sum of next 2 terms.** Sum2=2×18=36\text{Sum}_2 = 2 \times 18 = 36 **Step 3: Compute the overall mean of 5 numbers.** Mean=42+365=785=15.6\text{Mean} = \frac{42 + 36}{5} = \frac{78}{5} = 15.6 **Note:** The computed answer is 15.6 (Option D), not 14.5 (Option A). Let us recheck: 42+36=78\displaystyle 42+36=78, 78/5=15.6\displaystyle 78/5=15.6. The correct answer is **15.6**. Hence, **Option D** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

Related Comparison Tables

More Questions from Measures of Central Tendency and Dispersion

Ready to Master Measures of Central Tendency and Dispersion?

Practice all 473 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free