Central Tendency & DispersionMTP Nov 18Question 2887 of 454
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If the mean of the set of observations x1,x2,x3,,xn\displaystyle x_1, x_2, x_3, \dots, x_n is xˉ\displaystyle \bar{x}, then the mean of the observation xi+ki\displaystyle x_i + ki, where i=1,2,3,,n\displaystyle i = 1, 2, 3, \dots, n

Options

Axˉ+k(n+1)\displaystyle \bar{x} + k(n+1)
Bxˉ+kn\displaystyle \bar{x} + kn
Cxˉ+kn\displaystyle \bar{x} + \frac{k}{n}
Dxˉ+k2(n+1)\displaystyle \bar{x} + \frac{k}{2}(n+1)
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Correct Answer

Option axˉ+k(n+1)\displaystyle \bar{x} + k(n+1)

All Options:

  • Axˉ+k(n+1)\displaystyle \bar{x} + k(n+1)
  • Bxˉ+kn\displaystyle \bar{x} + kn
  • Cxˉ+kn\displaystyle \bar{x} + \frac{k}{n}
  • Dxˉ+k2(n+1)\displaystyle \bar{x} + \frac{k}{2}(n+1)

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