Central Tendency & DispersionMTP Nov 21Question 2900 of 473
All Questions

The average of 10 observations is 14.4. If the average of first four observations is 16.5. The average of remaining 6 observations is:

Options

A13.6
B13.0
C13.2
D12.5
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option b — 13.0

All Options:

  • A13.6
  • B13.0
  • C13.2
  • D12.5

Detailed Solution & Explanation

**Step 1: Compute total sum.** Total sum=10×14.4=144\text{Total sum} = 10 \times 14.4 = 144 **Step 2: Compute sum of first 4 observations.** Sum of first 4=4×16.5=66\text{Sum of first 4} = 4 \times 16.5 = 66 **Step 3: Find sum of remaining 6.** Sum of remaining 6=144−66=78\text{Sum of remaining 6} = 144 - 66 = 78 **Step 4: Compute average of remaining 6.** xˉremaining=786=13\bar{x}_{remaining} = \frac{78}{6} = 13 **Note:** The computed average is **13** (Option B), not 13.6 (Option A). Hence, **Option B** is the correct answer.

More Questions from Central Tendency & Dispersion

If the range of 28,22,40,20,15,50\displaystyle 28, 22, 40, 20, 15, 50 is

If the S.D. of the 1st\displaystyle 1^{st} n\displaystyle n natural numbers is 30\displaystyle \sqrt{30} then the value of n\displaystyle n is

If the variance of 5,7,9\displaystyle 5, 7, 9 and 11\displaystyle 11 is 4\displaystyle 4, then the coefficient of variation is:

A helicopter flies from A to B at the rate of 500 km/hr. and comes back at the rate 700 km/hr. The average speed of the helicopter is

If Arithmetic Mean (A.M.) and Geometric Mean (G.M.) of two numbers are 6.50 and 6 respectively, then the two numbers are

Which of the following is not a method of dispersion?

Ready to Master Central Tendency & Dispersion?

Practice all 473 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free