Measures of Central Tendency and DispersionMCQMTP March 22Question 2906 of 473
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If there are three observations 15,20,25\displaystyle 15, 20, 25, then the sum of deviation of the observations from their AM is.

Options

A0
B5
C-5
D10
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Correct Answer

✅ Option a — 0

All Options:

  • A0
  • B5
  • C-5
  • D10

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Detailed Solution & Explanation

**Step 1: Compute AM.** xˉ=15+20+253=603=20\bar{x} = \frac{15+20+25}{3} = \frac{60}{3} = 20 **Step 2: Compute algebraic sum of deviations.** (15−20)+(20−20)+(25−20)=−5+0+5=0(15-20) + (20-20) + (25-20) = -5 + 0 + 5 = 0 **Note:** The sum is **0** (Option A). The `correct_option` given as C (−5\displaystyle -5) is incorrect. The algebraic sum of deviations from AM is always zero by definition. Hence, **Option A** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

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