Central Tendency & DispersionMTP March 22Question 2906 of 473
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If there are three observations 15,20,25\displaystyle 15, 20, 25, then the sum of deviation of the observations from their AM is.

Options

A0
B5
C-5
D10
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Correct Answer

✅ Option a — 0

All Options:

  • A0
  • B5
  • C-5
  • D10

Detailed Solution & Explanation

**Step 1: Compute AM.** xˉ=15+20+253=603=20\bar{x} = \frac{15+20+25}{3} = \frac{60}{3} = 20 **Step 2: Compute algebraic sum of deviations.** (15−20)+(20−20)+(25−20)=−5+0+5=0(15-20) + (20-20) + (25-20) = -5 + 0 + 5 = 0 **Note:** The sum is **0** (Option A). The `correct_option` given as C (−5\displaystyle -5) is incorrect. The algebraic sum of deviations from AM is always zero by definition. Hence, **Option A** is the correct answer.

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