Central Tendency & DispersionMTP June 22Question 2907 of 473
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The mean weight of 15\displaystyle 15 students is 110\displaystyle 110 kg. The mean weight of 5\displaystyle 5 of them is 100\displaystyle 100 kg, and of another five students is 125\displaystyle 125 kg, then the mean weight of the remaining students is :

Options

A120
B105
C115
DNone of these
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Correct Answer

✅ Option b — 105

All Options:

  • A120
  • B105
  • C115
  • DNone of these

Detailed Solution & Explanation

**Step 1: Compute total weight of all 15 students.** Total=15×110=1650 kg\text{Total} = 15 \times 110 = 1650 \text{ kg} **Step 2: Compute weights of two known groups.** - Group 1 (5 students): 5×100=500\displaystyle 5 \times 100 = 500 kg - Group 2 (5 students): 5×125=625\displaystyle 5 \times 125 = 625 kg **Step 3: Find weight and mean of remaining 5 students.** Remaining students =15−5−5=5\displaystyle = 15 - 5 - 5 = 5 Sum of remaining=1650−500−625=525 kg\text{Sum of remaining} = 1650 - 500 - 625 = 525 \text{ kg} Mean=5255=105 kg\text{Mean} = \frac{525}{5} = 105 \text{ kg} **Note:** The computed mean is **105** (Option B), not 115 (Option C). Hence, **Option B** is the correct answer.

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