Measures of Central Tendency and DispersionMCQMTP June 22Question 2909 of 473
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The mean of first three terms is 14\displaystyle 14 and mean of next two terms is 18\displaystyle 18. The mean of all five terms is

Options

A14
B15
C14.5
D15.6
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Correct Answer

✅ Option d — 15.6

All Options:

  • A14
  • B15
  • C14.5
  • D15.6

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Detailed Solution & Explanation

**Step 1: Compute sum of first 3 terms.** Sum1=3×14=42\text{Sum}_1 = 3 \times 14 = 42 **Step 2: Compute sum of next 2 terms.** Sum2=2×18=36\text{Sum}_2 = 2 \times 18 = 36 **Step 3: Compute overall mean.** Mean=42+365=785=15.6\text{Mean} = \frac{42 + 36}{5} = \frac{78}{5} = 15.6 **Note:** The computed mean is **15.6** (Option D), not 14.5 (Option C). The correct answer is 15.6. Hence, **Option D** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

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