Central Tendency & DispersionMTP Dec 22 Series IQuestion 2911 of 473
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The mean of 100\displaystyle 100 students was 45\displaystyle 45. Later, it was discovered that the marks of two students were misread as 85\displaystyle 85 and 54\displaystyle 54 instead of 58\displaystyle 58 and 45\displaystyle 45. Find correct mean.

Options

A68
B36
C44.64
D52
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Correct Answer

✅ Option c — 44.64

All Options:

  • A68
  • B36
  • C44.64
  • D52

Detailed Solution & Explanation

**Step 1: Compute the original total sum.** Wrong sum=100×45=4500\text{Wrong sum} = 100 \times 45 = 4500 **Step 2: Correct the sum.** Wrong readings: 85 and 54 (sum = 139). Correct readings: 58 and 45 (sum = 103). Correct sum=4500−139+103=4500−36=4464\text{Correct sum} = 4500 - 139 + 103 = 4500 - 36 = 4464 **Step 3: Compute correct mean.** Correct mean=4464100=44.64\text{Correct mean} = \frac{4464}{100} = 44.64 **Note:** The correct mean is **44.64** (Option C), not 68 (Option A). Hence, **Option C** is the correct answer.

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