Central Tendency & DispersionMTP Dec 2023 Series IQuestion 2924 of 473
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The AM of 15\displaystyle 15 observations is 9\displaystyle 9 and the AM of first 9\displaystyle 9 observations is 11\displaystyle 11 and then AM of remaining observations is

Options

A11
B6
C5
D9
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Correct Answer

✅ Option b — 6

All Options:

  • A11
  • B6
  • C5
  • D9

Detailed Solution & Explanation

**Step 1: Total sum.** Total=15×9=135\text{Total} = 15 \times 9 = 135 **Step 2: Sum of first 9.** Sum9=9×11=99\text{Sum}_9 = 9 \times 11 = 99 **Step 3: Sum and mean of remaining 6.** Sumremaining=135−99=36\text{Sum}_{remaining} = 135 - 99 = 36 AMremaining=366=6\text{AM}_{remaining} = \frac{36}{6} = 6 **Note:** The correct AM is **6** (Option B). The `correct_option` given as D (9) is incorrect. Hence, **Option B** is the correct answer.

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