Central Tendency & DispersionMTP Dec 2023 Series IIQuestion 2925 of 411
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The weighted mean of first $n$ natural numbers, if their weights are proportional to their corresponding numbers is

Options

A$\frac{2n+1}{3}$
B$\frac{n-1}{2}$
C$\frac{n(n+1)(2n-1)}{6}$
D$\frac{3n(n+1)}{2}$
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Correct Answer

Option c$\frac{n(n+1)(2n-1)}{6}$

All Options:

  • A$\frac{2n+1}{3}$
  • B$\frac{n-1}{2}$
  • C$\frac{n(n+1)(2n-1)}{6}$
  • D$\frac{3n(n+1)}{2}$

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