Central Tendency & DispersionPYQ June 24 Series IQuestion 2937 of 473
All Questions

The mean of first 3 terms is 14 and the mean of next 2 terms is 18. The mean of 5 numbers is -

Options

A14.5
B15
C14
D15.6
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option d — 15.6

All Options:

  • A14.5
  • B15
  • C14
  • D15.6

Detailed Solution & Explanation

We are given: - Number of observations in the first group: n1=3\displaystyle n_1 = 3 - Mean of the first group: xˉ1=14\displaystyle \bar{x}_1 = 14 - Sum of observations of the first group: Sum1=3×14=42\displaystyle \text{Sum}_1 = 3 \times 14 = 42 - Number of observations in the second group: n2=2\displaystyle n_2 = 2 - Mean of the second group: xˉ2=18\displaystyle \bar{x}_2 = 18 - Sum of observations of the second group: Sum2=2×18=36\displaystyle \text{Sum}_2 = 2 \times 18 = 36 - Total number of observations: n=n1+n2=3+2=5\displaystyle n = n_1 + n_2 = 3 + 2 = 5 - Combined sum of all 5 observations: Sumtotal=42+36=78\displaystyle \text{Sum}_{\text{total}} = 42 + 36 = 78 Using the formula for the combined mean: xˉ=Sumtotaln=785=15.6\bar{x} = \frac{\text{Sum}_{\text{total}}}{n} = \frac{78}{5} = 15.6 Hence, **Option D** is the correct answer.

More Questions from Central Tendency & Dispersion

If the range of 28,22,40,20,15,50\displaystyle 28, 22, 40, 20, 15, 50 is

If the S.D. of the 1st\displaystyle 1^{st} n\displaystyle n natural numbers is 30\displaystyle \sqrt{30} then the value of n\displaystyle n is

If the variance of 5,7,9\displaystyle 5, 7, 9 and 11\displaystyle 11 is 4\displaystyle 4, then the coefficient of variation is:

A helicopter flies from A to B at the rate of 500 km/hr. and comes back at the rate 700 km/hr. The average speed of the helicopter is

If Arithmetic Mean (A.M.) and Geometric Mean (G.M.) of two numbers are 6.50 and 6 respectively, then the two numbers are

Which of the following is not a method of dispersion?

Ready to Master Central Tendency & Dispersion?

Practice all 473 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free