Measures of Central Tendency and DispersionMCQPYQ Nov 18Question 2949 of 473
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For 899,999,391,384,390,480,485,760,111,240\displaystyle 899, 999, 391, 384, 390, 480, 485, 760, 111, 240. Rank of median

Options

A2.75
B5.5
C8.25
DNone of these
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Correct Answer

Option b5.5

All Options:

  • A2.75
  • B5.5
  • C8.25
  • DNone of these

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Detailed Solution & Explanation

We are given the dataset containing n=10\displaystyle n = 10 observations: 899,999,391,384,390,480,485,760,111,240\displaystyle 899, 999, 391, 384, 390, 480, 485, 760, 111, 240. For a dataset with n\displaystyle n observations, the rank (or position) of the median is given by the formula: Rank of Median=n+12\text{Rank of Median} = \frac{n + 1}{2} Substituting n=10\displaystyle n = 10 into the formula: Rank of Median=10+12=112=5.5\text{Rank of Median} = \frac{10 + 1}{2} = \frac{11}{2} = 5.5 Hence, **Option B** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

Key Concepts to Understand

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