Central Tendency & DispersionPYQ Nov 18Question 2949 of 473
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For 899,999,391,384,390,480,485,760,111,240\displaystyle 899, 999, 391, 384, 390, 480, 485, 760, 111, 240. Rank of median

Options

A2.75
B5.5
C8.25
DNone of these
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Correct Answer

✅ Option b — 5.5

All Options:

  • A2.75
  • B5.5
  • C8.25
  • DNone of these

Detailed Solution & Explanation

We are given the dataset containing n=10\displaystyle n = 10 observations: 899,999,391,384,390,480,485,760,111,240\displaystyle 899, 999, 391, 384, 390, 480, 485, 760, 111, 240. For a dataset with n\displaystyle n observations, the rank (or position) of the median is given by the formula: Rank of Median=n+12\text{Rank of Median} = \frac{n + 1}{2} Substituting n=10\displaystyle n = 10 into the formula: Rank of Median=10+12=112=5.5\text{Rank of Median} = \frac{10 + 1}{2} = \frac{11}{2} = 5.5 Hence, **Option B** is the correct answer.

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