Central Tendency & DispersionPYQ Jun 23Question 2960 of 473
All Questions

The median of the following set of observation: 24,18,36,42,30,28,21,29,25,33\displaystyle 24, 18, 36, 42, 30, 28, 21, 29, 25, 33 is

Options

A26.5\displaystyle 26.5
B27.5\displaystyle 27.5
C28.5\displaystyle 28.5
D29.5\displaystyle 29.5
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option c — 28.5\displaystyle 28.5

All Options:

  • A26.5\displaystyle 26.5
  • B27.5\displaystyle 27.5
  • C28.5\displaystyle 28.5
  • D29.5\displaystyle 29.5

Detailed Solution & Explanation

We are given the observations: 24,18,36,42,30,28,21,29,25,33\displaystyle 24, 18, 36, 42, 30, 28, 21, 29, 25, 33. 1. Arrange the observations in ascending order: 18,21,24,25,28,29,30,33,36,4218, 21, 24, 25, 28, 29, 30, 33, 36, 42 Here, the number of observations is n=10\displaystyle n = 10 (which is even). 2. The median is the average of the two middle-most values (the 5th\displaystyle 5^{\text{th}} and 6th\displaystyle 6^{\text{th}} terms): - 5th\displaystyle 5^{\text{th}} term: 28\displaystyle 28 - 6th\displaystyle 6^{\text{th}} term: 29\displaystyle 29 3. Calculate the median: Median=28+292=572=28.5\text{Median} = \frac{28 + 29}{2} = \frac{57}{2} = 28.5 Hence, **Option C** is the correct answer.

More Questions from Central Tendency & Dispersion

Ready to Master Central Tendency & Dispersion?

Practice all 473 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free