Measures of Central Tendency and DispersionMCQPYQ Jun 23Question 2960 of 473
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The median of the following set of observation: 24,18,36,42,30,28,21,29,25,33\displaystyle 24, 18, 36, 42, 30, 28, 21, 29, 25, 33 is

Options

A26.5\displaystyle 26.5
B27.5\displaystyle 27.5
C28.5\displaystyle 28.5
D29.5\displaystyle 29.5
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Correct Answer

Option c28.5\displaystyle 28.5

All Options:

  • A26.5\displaystyle 26.5
  • B27.5\displaystyle 27.5
  • C28.5\displaystyle 28.5
  • D29.5\displaystyle 29.5

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Detailed Solution & Explanation

We are given the observations: 24,18,36,42,30,28,21,29,25,33\displaystyle 24, 18, 36, 42, 30, 28, 21, 29, 25, 33. 1. Arrange the observations in ascending order: 18,21,24,25,28,29,30,33,36,4218, 21, 24, 25, 28, 29, 30, 33, 36, 42 Here, the number of observations is n=10\displaystyle n = 10 (which is even). 2. The median is the average of the two middle-most values (the 5th\displaystyle 5^{\text{th}} and 6th\displaystyle 6^{\text{th}} terms): - 5th\displaystyle 5^{\text{th}} term: 28\displaystyle 28 - 6th\displaystyle 6^{\text{th}} term: 29\displaystyle 29 3. Calculate the median: Median=28+292=572=28.5\text{Median} = \frac{28 + 29}{2} = \frac{57}{2} = 28.5 Hence, **Option C** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

Key Concepts to Understand

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