Measures of Central Tendency and DispersionMCQMTP Apr 21Question 2976 of 473
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The median of data 13,8,11,6,4,15,2,18\displaystyle 13, 8, 11, 6, 4, 15, 2, 18 is

Options

A8\displaystyle 8
B9\displaystyle 9
C11\displaystyle 11
D9.5\displaystyle 9.5
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Correct Answer

Option d9.5\displaystyle 9.5

All Options:

  • A8\displaystyle 8
  • B9\displaystyle 9
  • C11\displaystyle 11
  • D9.5\displaystyle 9.5

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Detailed Solution & Explanation

To find the median of the data: 13,8,11,6,4,15,2,18\displaystyle 13, 8, 11, 6, 4, 15, 2, 18: 1. Arrange the data in ascending order: 2,4,6,8,11,13,15,182, 4, 6, 8, 11, 13, 15, 18 Here, the number of observations is n=8\displaystyle n = 8 (which is even). 2. The median is the average of the two middle-most values (the 4th\displaystyle 4^{\text{th}} and 5th\displaystyle 5^{\text{th}} values): - 4th\displaystyle 4^{\text{th}} value: 8\displaystyle 8 - 5th\displaystyle 5^{\text{th}} value: 11\displaystyle 11 3. Calculate the median: Median=8+112=192=9.5\text{Median} = \frac{8 + 11}{2} = \frac{19}{2} = 9.5 Hence, **Option D** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

Key Concepts to Understand

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