Central Tendency & DispersionMTP Apr 21Question 2976 of 473
All Questions

The median of data 13,8,11,6,4,15,2,18\displaystyle 13, 8, 11, 6, 4, 15, 2, 18 is

Options

A8\displaystyle 8
B9\displaystyle 9
C11\displaystyle 11
D9.5\displaystyle 9.5
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option d — 9.5\displaystyle 9.5

All Options:

  • A8\displaystyle 8
  • B9\displaystyle 9
  • C11\displaystyle 11
  • D9.5\displaystyle 9.5

Detailed Solution & Explanation

To find the median of the data: 13,8,11,6,4,15,2,18\displaystyle 13, 8, 11, 6, 4, 15, 2, 18: 1. Arrange the data in ascending order: 2,4,6,8,11,13,15,182, 4, 6, 8, 11, 13, 15, 18 Here, the number of observations is n=8\displaystyle n = 8 (which is even). 2. The median is the average of the two middle-most values (the 4th\displaystyle 4^{\text{th}} and 5th\displaystyle 5^{\text{th}} values): - 4th\displaystyle 4^{\text{th}} value: 8\displaystyle 8 - 5th\displaystyle 5^{\text{th}} value: 11\displaystyle 11 3. Calculate the median: Median=8+112=192=9.5\text{Median} = \frac{8 + 11}{2} = \frac{19}{2} = 9.5 Hence, **Option D** is the correct answer.

More Questions from Central Tendency & Dispersion

Ready to Master Central Tendency & Dispersion?

Practice all 473 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free