Central Tendency & DispersionMTP March 22Question 2979 of 473
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The median value of the set of observations 48,36,72,87,19,66,56\displaystyle 48, 36, 72, 87, 19, 66, 56 and 91\displaystyle 91

Options

A53\displaystyle 53
B87\displaystyle 87
C61\displaystyle 61
D19\displaystyle 19
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Correct Answer

✅ Option c — 61\displaystyle 61

All Options:

  • A53\displaystyle 53
  • B87\displaystyle 87
  • C61\displaystyle 61
  • D19\displaystyle 19

Detailed Solution & Explanation

We are given the set of observations: 48,36,72,87,19,66,56,91\displaystyle 48, 36, 72, 87, 19, 66, 56, 91. 1. Arrange the observations in ascending order: 19,36,48,56,66,72,87,9119, 36, 48, 56, 66, 72, 87, 91 Here, the number of observations is n=8\displaystyle n = 8 (which is even). 2. The median is the average of the two middle-most values (the 4th\displaystyle 4^{\text{th}} and 5th\displaystyle 5^{\text{th}} values): - 4th\displaystyle 4^{\text{th}} value: 56\displaystyle 56 - 5th\displaystyle 5^{\text{th}} value: 66\displaystyle 66 3. Calculate the median: Median=56+662=1222=61\text{Median} = \frac{56 + 66}{2} = \frac{122}{2} = 61 Hence, **Option C** is the correct answer.

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