Measures of Central Tendency and DispersionMCQMTP June 22/ MTP Sep 24 IQuestion 2980 of 473
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The first Quartile is 142\displaystyle 142 and Semi-inter Quartile Range is 18\displaystyle 18, then the value of Median is:

Options

A151\displaystyle 151
B160\displaystyle 160
C178\displaystyle 178
DNone of these
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Correct Answer

Option b160\displaystyle 160

All Options:

  • A151\displaystyle 151
  • B160\displaystyle 160
  • C178\displaystyle 178
  • DNone of these

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Detailed Solution & Explanation

We are given: - First quartile: Q1=142\displaystyle Q_1 = 142 - Semi-interquartile range (Quartile Deviation, Q.D.): Q.D.=18\displaystyle \text{Q.D.} = 18 For a symmetric distribution, the quartiles are symmetric about the median, which means: Q.D.=Q3Q12    Q3Q1=2(18)=36    Q3=142+36=178\text{Q.D.} = \frac{Q_3 - Q_1}{2} \implies Q_3 - Q_1 = 2(18) = 36 \implies Q_3 = 142 + 36 = 178 Also, the median is the midpoint of Q1\displaystyle Q_1 and Q3\displaystyle Q_3: Median=Q1+Q32=142+1782=3202=160\text{Median} = \frac{Q_1 + Q_3}{2} = \frac{142 + 178}{2} = \frac{320}{2} = 160 Alternatively, we can directly compute: Median=Q1+Q.D.=142+18=160\text{Median} = Q_1 + \text{Q.D.} = 142 + 18 = 160 Hence, **Option B** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

Key Concepts to Understand

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