Central Tendency & DispersionMTP June 2023 Series IQuestion 2984 of 473
All Questions

The median of the observations 42,72,35,92,67,85,72,81,51,56\displaystyle 42, 72, 35, 92, 67, 85, 72, 81, 51, 56 is

Options

A69.5\displaystyle 69.5
B72\displaystyle 72
C64\displaystyle 64
D61.5\displaystyle 61.5
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option a — 69.5\displaystyle 69.5

All Options:

  • A69.5\displaystyle 69.5
  • B72\displaystyle 72
  • C64\displaystyle 64
  • D61.5\displaystyle 61.5

Detailed Solution & Explanation

We are given the observations: 42,72,35,92,67,85,72,81,51,56\displaystyle 42, 72, 35, 92, 67, 85, 72, 81, 51, 56. 1. Arrange the data in ascending order: 35,42,51,56,67,72,72,81,85,9235, 42, 51, 56, 67, 72, 72, 81, 85, 92 Here, the number of observations is n=10\displaystyle n = 10. 2. The median is the average of the two middle-most observations (the 5th\displaystyle 5^{\text{th}} and 6th\displaystyle 6^{\text{th}} observations): - 5th\displaystyle 5^{\text{th}} observation: 67\displaystyle 67 - 6th\displaystyle 6^{\text{th}} observation: 72\displaystyle 72 3. Calculate the median: Median=67+722=1392=69.5\text{Median} = \frac{67 + 72}{2} = \frac{139}{2} = 69.5 Hence, **Option A** is the correct answer.

More Questions from Central Tendency & Dispersion

Ready to Master Central Tendency & Dispersion?

Practice all 473 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free