Central Tendency & DispersionMTP Mar 22Question 3007 of 473
All Questions

If two variables a\displaystyle a and b\displaystyle b are related by c=ab\displaystyle c = ab then GM. of c\displaystyle c =

Options

AGM of a\displaystyle a + GM of b\displaystyle b
BGM of a×\displaystyle a \times GM of b\displaystyle b
CGM of a\displaystyle a - GM of b\displaystyle b
DGM of a\displaystyle a / GM of b\displaystyle b
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Correct Answer

✅ Option b — GM of a×\displaystyle a \times GM of b\displaystyle b

All Options:

  • AGM of a\displaystyle a + GM of b\displaystyle b
  • BGM of a×\displaystyle a \times GM of b\displaystyle b
  • CGM of a\displaystyle a - GM of b\displaystyle b
  • DGM of a\displaystyle a / GM of b\displaystyle b

Detailed Solution & Explanation

**Step 1: Recall the fundamental property of Geometric Mean.** For n\displaystyle n paired observations where ci=ai⋅bi\displaystyle c_i = a_i \cdot b_i: GM(c)=(∏i=1nci)1/n=(∏i=1naibi)1/n\text{GM}(c) = \left(\prod_{i=1}^{n} c_i\right)^{1/n} = \left(\prod_{i=1}^{n} a_i b_i\right)^{1/n} =(∏i=1nai)1/n×(∏i=1nbi)1/n=GM(a)×GM(b)= \left(\prod_{i=1}^{n} a_i\right)^{1/n} \times \left(\prod_{i=1}^{n} b_i\right)^{1/n} = \text{GM}(a) \times \text{GM}(b) **Step 2: Conclusion.** If c=ab\displaystyle c = ab, then GM(c)=GM(a)×GM(b)\displaystyle \text{GM}(c) = \text{GM}(a) \times \text{GM}(b). This matches **Option B** (GM of a\displaystyle a × GM of b\displaystyle b). Note: The given correct option is D, but mathematically when c=a×b\displaystyle c = a \times b, GM(c)\displaystyle (c) = GM(a)\displaystyle (a) × GM(b)\displaystyle (b), which is **Option B**. (If c=a/b\displaystyle c = a/b, then GM(c)\displaystyle (c) = GM(a)\displaystyle (a)/GM(b)\displaystyle (b) = Option D.) Hence, **Option B** is the correct answer.

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