Measures of Central Tendency and DispersionMCQMTP Nov 19Question 3012 of 473
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A person travels from A to B at the rate of 20 km/hr\displaystyle 20 \text{ km/hr} and from B to A at the rate of 30 km/hr\displaystyle 30 \text{ km/hr}. What is the average rate of whole journey?

Options

A30 km/hr\displaystyle 30 \text{ km/hr}
B24 km/hr\displaystyle 24 \text{ km/hr}
C35 km/hr\displaystyle 35 \text{ km/hr}
DNone of these
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Correct Answer

Option b24 km/hr\displaystyle 24 \text{ km/hr}

All Options:

  • A30 km/hr\displaystyle 30 \text{ km/hr}
  • B24 km/hr\displaystyle 24 \text{ km/hr}
  • C35 km/hr\displaystyle 35 \text{ km/hr}
  • DNone of these

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Detailed Solution & Explanation

**Step 1: Apply the harmonic mean formula for equal distances.** Average speed=2v1v2v1+v2\text{Average speed} = \frac{2 v_1 v_2}{v_1 + v_2} **Step 2: Substitute values.** - v1=20\displaystyle v_1 = 20 km/hr, v2=30\displaystyle v_2 = 30 km/hr Average speed=2×20×3020+30=120050=24 km/hr\text{Average speed} = \frac{2 \times 20 \times 30}{20 + 30} = \frac{1200}{50} = 24 \text{ km/hr} **Verification:** Let distance AB=d\displaystyle AB = d. Total distance =2d\displaystyle = 2d. Total time =d20+d30=3d+2d60=5d60=d12\displaystyle = \frac{d}{20} + \frac{d}{30} = \frac{3d + 2d}{60} = \frac{5d}{60} = \frac{d}{12}. Average speed =2dd/12=24\displaystyle = \frac{2d}{d/12} = 24 km/hr ✓ Hence, **Option B** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

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