Central Tendency & DispersionMTP Nov 18Question 3014 of 454
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The Geometric mean of the series 1,k,k2,k3,...,kn\displaystyle 1, k, k^2, k^3, ..., k^n where k\displaystyle k is constant is

Options

Akn+1\displaystyle k^{n+1}
Bkn+0.5\displaystyle k^{n+0.5}
Ckn+12\displaystyle k^{\frac{n+1}{2}}
Dkn+2\displaystyle k^{n+2}
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Correct Answer

Option bkn+0.5\displaystyle k^{n+0.5}

All Options:

  • Akn+1\displaystyle k^{n+1}
  • Bkn+0.5\displaystyle k^{n+0.5}
  • Ckn+12\displaystyle k^{\frac{n+1}{2}}
  • Dkn+2\displaystyle k^{n+2}

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